Is n(n - 1) odd or even

n(n-1) is even for all integers.

Step-by-step explanation:

We have:

And we would like to determine its parity.

Case 1: n is Even:

If n is even, then we will have an even number (n) multiplied by an odd number (n-1).

Since anything multiplied by an even number is even, n(n-1) is even for all even values.

Care 2: n is Odd:

If n is odd, then we will still have an odd number (n) multiplied by an even number (n-1).

And again, this will yield an even number.

Therefore, n(n-1) will be even for all integers.  

he answer is x=1x3 because x=1 to x=3