three numbers have a sum of 112. The first number is twice the second, and the third number is twice the first. What is the smallest of the three numbers?

The second number is the smallest of the three numbers with

value n = 16.

Step-by-step explanation:

Let n represent the second number, then the first number is 2n and the third number is 4n.

so

Solving for n

As n = 16 is the second number.

The first number = 2n = 2(16) = 32

The third number = 4n = 4(16) = 64

Therefore, the second number is the smallest of the three numbers with value n = 16.