Can anyone tell me what this graph is in slope intercept form?

the standard form equation is 1/2x^2-x-3/2=0

the vertex form equation is  1/2(x-1)^2-2=0

Step-by-step explanation:

Unfortunately, this can't be written in slope intercept form but I can write it in standard form(ax^2+bx+c) or vertex form (a(x-h)+k)

The vertex is (1,-2)

I estimate a=1/2 because the graph was widened and that can only be done by a fraction.

So, 1/2(x-1)^2-2=0

To find it in standard form

foil (x-1)(x-1)= x^2-2x+1

Then multiply by 1/2(x^2-2x+1)= 1/2x^2-x+1/2-2

To add 1/2-2. You mulitply -2 by 2/2 which equals 1/2-4/2 which equals -3/2

So the standard form equation is 1/2x^2-x-3/2=0

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

c-   36

taxicab circle radius 9 has 4(9) = 36 points