Determine the x- and y- intercepts for the graph defined by the given equation. y = x + 8
a. x-intercept is (0,8)
c. x-intercept is (-8, 0)
y-intercept is (-8, 0)
y-intercept is (0,8)
b. x-intercept is (0, -8)
d. x-intercept is (8,0)
y-intercept is (8,0)
y-intercept is (0, -8)

y-intercept is (0,8)

c. x-intercept is (-8, 0)

Step-by-step explanation:

y=x+8

x=0

y+0=8

y=8

y=0

y=x+8

0=x+8

x=-8

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

7

step-by-step explanation: