Transform the given standard form into vertex form and determine vertex. 1.y=x²-4x-3

2.y=x²-7x+2

1. the vertex form of your function is f(x)= (x+-2)^2+-7

The vertex is at (2,-7)

2. So, the vertex form of your function is f(x)= (x+-7/2)^2 -41/4

The vertex is at (7/2, -41/4)

Step-by-step explanation:

a negative exponent is translated as follows:

so, we have

its an acute right triangle

step-by-step explanation: