In a two-digit number, the first digit is 5 less than the second digit. The number itself is three times the sum of its digits. What is the number? (I WILL MARK BRAINLIEST)

27

Step-by-step explanation:

taking the second digit as 'x'

as per question the first digit is 'x-5'

therefore putting this in the one, tens, hundreds form

u multiply the first digit by 10 and the second by 1

therefore,

10(x-5) + 1(x)

now you have that the 2-digit number is equal to twice the sum of the digits,

so

10(x-5) + 1(x) = 3 [ (x-5) + (x) ]

on solving

10x - 50 + x = 3 (2x - 5)

11x -50 = 6x - 15

taking 6x on the right and -50 on the left

11x - 6x = 50 - 15

5x = 35

therefore x = 7

now substituting this value we get that the number is

27

x + 4/7

step-by-step explanation:

use cymath