Which identity is the result of using the pythagorean theorem to show that a triangle with side lengths x^2 - 1, 2x, and x^2 + 1 is a right triangle? A. (x^2 - 1)^2 + (2x)^2 = -(x^2 + 1)^2
B. -(x^2 -1)^2 + (2x)^2 = (x^2 +1)^2
C. (x^2-1)^2 + (2x)^2 = (x^2 +1)^2
D. (x^2 - 1)^2 - (2x)^2 = (x^2 + 1)^2

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  C.  (x^2-1)^2 + (2x)^2 = (x^2 +1)^2

Step-by-step explanation:

Inexplicably, three of the four answer choices have minus signs in them. Those are all incorrect. The appropriate choice is ...

  C. (x^2-1)^2 + (2x)^2 = (x^2 +1)^2

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Expanded, this is ...

  x^4 -2x^2 +1 +4x^2 = x^4 +2x^2 +1 . . . . the desired identity

you divide them and then you get the answer i took this class this year

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9