Zoey invested $230 in an account paying an interest rate of 6.3% compounded daily. Assuming no deposits or withdrawals are made, how much money, to the nearest
hundred dollars, would be in the account after 12 years?

A ≈ $500

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Algebra I

Compounded Interest Rate: A = P(1 + r/n)ⁿˣ

A is final amountP is initial (principle) amountr is raten is number of compoundsx is number of years

Step-by-step explanation:

Step 1: Define

P = 230

r = 0.063

n = 365

x = 12

Step 2: Solve for A

Substitute:                    A = 230(1 + 0.063/365)³⁶⁵⁽¹²⁾Divide:                          A = 230(1 + 0.000173)³⁶⁵⁽¹²⁾Multiply:                        A = 230(1 + 0.000173)⁴³⁸⁰Add:                              A = 230(1.00017)⁴³⁸⁰Exponents:                   A = 230(2.1296)Multiply:                        A = 489.808

Where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis. to write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope. this is the value of m in the equation.

The graph isn’t that clear