1/8 (-8c+16) - 1/3(6 + 3c) =

-2c

Step-by-step explanation: hope this helps! :)

-2c

Step-by-step explanation:

1/8(-8c+16)-1/3(6+3c) Simplify

1/3(6+3c) = 2+C

= (-c+2)-(c+2)

Remove parentheses  with  (-a) = a

=- -c+2-(2+c)

simplify

-2-c

=-c+2-2-c simplify

= -2c

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.