Help me pls T^T ASAP What are the conjugate and modulus of –14 – 2i?

A.) 14 + 2i and 8 StartRoot 3 EndRoot
B.) 14 + 2i and 10 StartRoot 2 EndRoot
C.) –14 + 2i and 8 StartRoot 3 EndRoot
D.) –14 + 2i and 10 StartRoot 2 EndRoot

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .