What is the equation of a line that passes through the points (-3,3) and (-1,-3)?

y= -3x +12

Step-by-step explanation:

m=

m=

m=

m=-3

y=mx+c

y= -3x +c

substitute (-3;3)

3= -3(3)+c

3=-9+c

3+9=c

c=12

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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