. Square KLMN with vertices K(0,2), L(1,8), M(7,7), and N(6, 1): 270 counterclockwise about the orgin

Note: Consider we need to find the vertices of the image.

Given:

Square KLMN with vertices K(0,2), L(1,8), M(7,7), and N(6, 1).

It rotates 270 counterclockwise about the origin.

To find:

The vertices of the image after rotation.

Solution:

If a figure rotates 270 counterclockwise about the origin, then the rule of rotation is defined as

Using this rule, we get

Therefore, the vertices of the image are K'(2,0), L'(8,-1), M'(7,-7) and N'(1,-6).

If a figure rotates 270 counterclockwise about the origin, then the rule of rotation is defined as

Using this rule, we get

k(0,2)=(2,0)

l(1,8)=(8,-1)

m(7,7)=(7,-7)

n(6,1)=(1,-6)

I think it helps you

step-by-step explanation:

(s)he  is right it would be 5.5% because it is smaller than 15.5% or anything smaller than 15.5% in general

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.