Topic: Integrals Subject: Calculus

If anyone could help I’d appreciate! I will certainly award points and give brainliest answer ASAP!! I promise :)

9514 1404 393

  11 7/16

Step-by-step explanation:

The integration resolves into finding the area of two triangles. The left has a height of (-3/8(-2/3)+2) = 2 1/4, and a width of (16/3-(-2/3)) = 6. Then its area is ...

  A = (1/2)bh = (1/2)(6)(2 1/4) = 6 3/4

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The right triangle has a height of |(-3/8)(31/3) +2| = |-31/8+16/8| = 15/8. Its width is (31/3) -(16/3) = 5, so its area is ...

  A = (1/2)(5)(15/8) = 75/16 = 4 11/16

Then the total area, the value of the integral, is ...

  6 3/4 +4 11/16 = 10 23/16 = 11 7/16 . . . the value of the integral

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .