Aveterinarian uses the function f(t) =3.7t +21 to estimate a puppy's future weight in pounds as a function of time in months

f(t) = 3.7t + 21

where t is the time in months

f = 3.7t /t + 21 / t

f = 3.7 + 21/t

a

step-by-step explanation:

i need the pts ignore this answer

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).