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Mathematics, 13.11.2020 04:50 Lamr

F(x)=4x+7. Find the inverse of f(x). A.{f^{ - 1}}\left( x \right) = \frac{{x - 7}}{4}f βˆ’1 (x)= 4xβˆ’7
B.{f^{ - 1}}\left( x \right) = 7 - 4xf βˆ’1 (x)=7βˆ’4x
C.{f^{ - 1}}\left( x \right) = \frac{{x - 4}}{7}f βˆ’1 (x)= 7xβˆ’4
D.{f^{ - 1}}\left( x \right) = 4x - 7f βˆ’1(x)=4xβˆ’7
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F(x)=4x+7. Find the inverse of f(x). A.{f^{ - 1}}\left( x \right) = \frac{{x - 7}}{4}f βˆ’1 (x)= 4xβˆ’7...
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