A small town has two local high schools. High School A currently has 850 students and is projected to grow by 35 students each year. High School B currently has 700 students and is projected to grow by 60 students each year. Let AA represent the number of students in High School A in tt years, and let BB represent the number of students in High School B after tt years. Write an equation for each situation, in terms of t, t, and determine after how many years, t, t, the number of students in both high schools would be the same.

An equation for each situation, in terms of t, is y = 850e^35t and

y = 700e^70t

The required equation will be in the form y = Ae^kt

where:

If High School A currently has 850 students and is projected to grow by 35 students each year, hence;

Substituting into the formula, we will have:

y = 850e^35t

If High School B currently has 700 students and is projected to grow by 60 students each year, hence;

Substituting into the formula, we will have:

y = 700e^70t

An equation for each situation, in terms of t, is y = 850e^35t and

y = 700e^70t

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3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.