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One solution each is given for four quadratic equations. Assuming that each quadratic equation has two solutions, what is the second solution
for each equation?
I= 5 + 4i
I= 4 - 5
1 =
-5
4i
1 =
-4 + 51
I = 4 + 51
>
I = 5 - 4
= - 4 - 5
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Step-by-step explanation:

If one solution of a quadratic equation is a complex number (a + bi),

Other solution of the equation will be the conjugate of the first solution.

So the other solution will be in the form of (a - bi)

If one solution is, x = -4 - 5i

Other solution will be, x = -4 + 5i

If one solution is, x = 4 + 5i

Other solution will be, x = 4 - 5i

If one solution is, x = 5 - 4i

Other solution will be, x = 5 - 4i

I believe if wrong sorry :(

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8