Acoffee mixture has beans that sell for $0.20 a pound and beans that sell for $0.68. if 120 pounds of beans create a mixture worth $0.54 a pound, how much of each bean is used? model the scenario then solve it. then, in two or more sentences explain whether your solution is or is not reasonable.

Beans that sell for 0.2 aer t
beans that sell for 0.68 are s

total is 120 pounds
s+t=120

cost is
0.2t+0.68s=0.54*120

solve

0.2t+0.68s=0.54*120
0.2t+0.68s=64.8
multilpy boht sides by 10
2t+6.8s=648
divide boht sides by 2
t+3.4s=324
other equaiton
t+s=120
multily this equaiton by -1 and add to other equaiation

-t-s=-120
t+3.4s=324 +
0t+2.4s=204

2.4s=204
divide both sides by 2.4
s=85
sub back

s+t=85
85+t=120
minus both sides 85
t=35

35 pounds of the $0.20 variety
85 pounds of the 0.68 variety

check
35*0.20+85*0.68=
7+57.8=
64.8

120*0.54=64.8

64.8=64.8

my answer is reasonable

35lb of $0.20 beans
85lb of $0.68 beans