Asha borrowed Rs.24000 from a moneylender at a rate of 4% per annum compounded semi annually ,what payment will she have to make after 1year and 6 months to the moneylender to clear her debt ?

Rs. 25,468.8

Step-by-step explanation:

A = p(1 + r/n)^nt

Where,

P = principal = RS. 24,000

r = interest rate = 4%= 0.04

n = number of periods = 2

t = years = 1 year and 6 months = 1.5 years

A = p(1 + r/n)^nt

= 24,000(1 + 0.04/2)^2*1.5

= 24,000(1 + 0.02)^3

= 24,000(1.02)^3

= 24,000( 1.0612)

= 25,468.8

A = Rs. 25,468.8

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.