A new youth sports center is being built in a safe harbor. The perimeter of the rectangular playing field is 510 yards. The length is the field is 5 yards less than quadruple the width. What are the dimensions of the plying field?

Step-by-step explanation:

Step one:

given data

perimeter= 510 yards

let the width be x, width=x

length= (4x-5)quadruple mean 4 times

Step two:

the expression for perimeter is

P=2L+2W

510=2(4x-5)+2x

510=8x-10+2x

510+10=8x+2x

520=10x

divide both sides by 10

x=520/10

x=52

the width is 52 yards

the lenght is  (4x-5)

L=4(52)-5

L=208-5

L=203 yards