At a birthday party pizzas and sodas were purchased for the kids. The number of sodas bought was two more than three times the number of pizzas. Pizzas cost $9.50 each and sodas cost $1.25 each. (c) A total of $68.75 was spent on pizza and sodas at the party. Let n be the number of pizzas purchased. Set up an equation involving n that models the scenario. Solve it and state both the number of pizzas and the number of sodas that were bought.

5 pizzas and 17 sodas were bought

Step-by-step explanation:

Here, we want to get the number of pizza and sodas bought

Let n be the number of pizzas bought

we are told that the number of sodas bought was 2 more than 3 times the number of pizzas

So the number of sodas will be;

3n + 2

So let’s have the equations based on the prices;

pizzas cost $9.50, soda cost $1.25

Thus;

9.5n + 1.25(3n + 2) = 68.75

9.5n + 3.75n + 2.5 = 68.75

13.25n = 68.75 - 2.5

13.25n = 66.25

n = 66.25/13.25

n = 5

Number of pizzas bought is 5

number of soda is 3n + 2 = 3(5) + 2 = 15 + 2 = 17

ik how do do this just give me a few minutes and i will give it to

(x+3)(x+7)

step-by-step explanation: