One moving company charges 760 plus 20 per hour. Another moving company charges 820 plus 14 per hour. For how many hours do the companies charge the same Choose a variable for the unknown quantity and write an equation to model the situation. Solve the equation to find the numbers of hours. Then find the charge. Let t represent the number of hours for which the charges are the same 820 + Blank T = 760 + blank T

4.0 ft

step-by-step explanation:

4.0 ft

the answer is b

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100