Let the factors, a1, a2, … a9 of a9 be written in a square 3 by 3 array as indicated. Let a1 Help me plz

61.2

Step-by-step explanation:

To solve this, we would have to use the arithmetic progression formula

S(n) = a + (n - 1) d, where

S(n) = is the value of the nth term

a = value of the first term

n = the nth term we're interested in

d = difference between successive terms

We're given that the first term, a1 = 1.we also know that the 6th term, a6 = 44

If so, we can use this to get our "d", saying

44 = 1 + (6 - 1) d

where

44 is the value of the 6th term, and n is 6. Also, the first term a = 1. Simplifying further we have

44 = 1 + 5d

5d = 44 - 1

5d = 43

d = 43/5

d = 8.6

This means that the difference between successive term is 8.6, we then use this "d" to find our 8th term

S(n) = 1 + (8 - 1) 8.6

S(n) = 1 + 7 * 8.6

S(n) = 1 + 60.2

S(n) = 61.2

Therefore, the 8th term is 61.2

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10