Three cubic feet of seawater weigh 192 pounds. What is the weight of the seawater in an aquarium that is 4.4 ft long, 2.5 ft wide, and 5.3 ft high?

3731.2 pounds

Step-by-step explanation:

Aquarium will hold 4.4 * 2.5 * 5.3 = 58.3 cubic feet of sea water.

For 3 cubic feet of sea water, weight is 192 pounds

For 58.3 cubic feet of sea water,

( 192 * 58.3) / 3 = 11193.6 / 3 = 3731.2 pounds

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

hope to and hope that my answer is brainliest.(follow me )