A polling agency is investigating the voter support for a ballot measure in an upcoming city election. The agency will select a random sample of 400 voters from one region, Region A, of the city. Assume that the population proportion of voters who would support the ballot measure in Region A is 0.46. Required:
What is the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50?

0.0544

Step-by-step explanation:

From the given information;

The population proportion of the voters that would support the ballot measures in region A = 0.46

The random sample n = 400 voters

The required probability can therefore be computed as follows:

Using the Excel Function =NORMDIST(1.605)

Therefore, the required probability = 0.0544

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

the first option is the answer.