After collecting the data, Christopher finds that the total snowfall per year in Reamstown is normally distributed with mean 94 inches and standard deviation 14 inches. What is the probability that, in a randomly selected year, the snowfall was greater than 52 inches?

0.9987

Step-by-step explanation:

Using Z score formula

z = (x-μ)/σ, where

x is the raw score = 52 inches

μ is the population mean = 94 inches

σ is the population standard deviation = 14 inches

z = 52 - 94/14

z =-3

Probability value from Z-Table:

P(x<52) = 0.0013499

P(x>52) = 1 - P(x<52)

P(x>52) = 1 - 0.0013499

= 0.99865

Therefore, the probability that, in a randomly selected year, the snowfall was greater than 52 inches is approximately 0.9987

3+3+3+2*2*2+29*12 = 365

step-by-step explanation:

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6