Applicants to a psychology department have normally distributed GRE scores with a mean, LaTeX: \muμ, of 544 and a standard deviation, LaTeX: \sigmaÏ, of 103. What percentage of applicants scored between 500 and 700? Round to the nearest percent. A. -24% B. 78% C. 2296 D. 24% E. 5%

The probability is P(500 < X  < 700 ) =  0.60044

Step-by-step explanation:

From the question we are told that

    The mean is  

     The standard deviation is  

Generally the percentage of applicant that scored between 500 and 700 is mathematically represented as

=>  

Generally from the z-table, the area under the normal curve to the left corresponding to    1.5146 and     -0.4272  is

  P(  Z<  1.5146 )  =  0.93506

   P ( Z <   -0.4272 ) = 0.33462

So

       P(500 < X  < 700 ) =  0.93506 -  0.33462

=>    P(500 < X  < 700 ) =  0.60044

congruent segments

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%