The rectangle has length 8 cm and area 48 cm2. The perimeter of the square is the same as the perimeter of the rectangle.

Calculate the area of the square.

The area of the square based on the information is 49cm².

Since the rectangle has length 8 cm and area 48 cm², the width will be:

= 48/8 = 6cm.

Therefore, the perimeter will be:

= 2(l + w)

= 2(8 + 6)

= 28cm

Therefore, the length of the square will be:

= 28/4 = 7

Area of the square will be:

= 7cm × 7cm

= 49cm²

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Step-by-step explanation:

Given,

length of rectangle(l)= 8cm

area of rectangle(A) = 48cm2

breadth of rectangle(b) = ?

Perimeter of rectangle (P)=?

We know ,

Area of rectangle(A) = l×b

or, 48cm2 = 8cm×b

or, 48cm2 = 8bcm

or, 48cm2/8cm = b

or, 6cm = b

or, b = 6cm

therefore, b = 6cm

Perimeter of rectangle (P) = 2(l+b)

= 2(8cm+6cm)

= 2×14cm

= 28cm

therefore, Perimeter of rectangle(P) = 28cm

Now,

According to the question,

Perimeter of rectangle(P) = Perimeter of square(P)

So,

Perimeter of square(P) = 28cm

length of square(l) = ?

Area of square (A) = ?

We know,

Perimeter of square (P) = 4l

or, 28cm = 4l

or, 28cm/4 = l

or, 7cm = l

or, l = 7cm

therefore, l = 7cm

Now,

Area of square (A) = l^2

= (7cm)^2

= 7cm×7cm

= 49cm^2

therefore, area of square (A)= 49cm^2

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