Stacy, oliver, and jivesh each plan to put a certain amount of money into their savings accounts that earn simple interest of 6% per year. stacy puts $550 more than jivesh, and oliver puts in 2 times as much as jivesh. after a year, the amount in stacy's account is 2 times the sum of $212 and the amount in oliver's account. how much does each person initially put into his or her account? who has the most money in his or her account after a year? who had the least? explain.

Jivesh put $50 Stacy $600 and Oliver $100.

Step-by-step explanation:

Consider the provided information.

Let the amount Jivesh put is represented by x.

Stacy puts $550 more than Jivesh, and Oliver puts in 2 times as much as Jivesh.

That means Stacy= x+550 and Oliver = 2x

After a year, the amount in Stacy's account is 2 times the sum of $212 and the amount in Oliver's account.

After 2 yrs.

The amount in Oliver's account = 106%(2x) or 1.06(2x)

The amount in Stacy's account = 2(212+1.06(2x)) (1)

As we know the Stacy put x+550 in his account so after 2 yrs the amount will be:

1.06(x+550) (2)

By equation 1 and 2.

212+1.06(2x)=0.53(x+550)

212+2.12x=0.53x+291.5

1.59x=79.5

x=50

Hence, Jivesh put $50.

Stacy = 50+550 = $600

Oliver = 2(50) = $100

i can you with this question sweetie!

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )