Solve the problem involving consecutive integers. If three times the smaller of two consecutive integers is added to four times the larger, the result is 109. Find the smaller integer.
A. 14 B. 45 C. 15 D. 16

c.15

Step-by-step explanation:

smaller integer=x

larger integer=x+1

3x+4(x+1)=109

3x+4x+4=109

7x+4=109

7x=105

x=105/7

x=15

check:

3(15)+4(15+1)=109

45+64=109

t hope this

:

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant