A man is 13 times as old as his son is. In 10 years he will be 3 times as old as his son is now. How old are they now?

the son is 2

man is 26

+10 yrs

son=12

man=36

Step-by-step explanation:

Let the son's age be x.

Then the father's age is 13x.

In ten years their ages will be (x+10) and (13x+10).

(13x+10)=3(x+10)

13x+10=3x+30

10x=20

x=2

The son is 2 years old.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: