Please help me idk how to do this

y = 2(x-2)^2+5

Step-by-step explanation:

Vertex form is y - h = a ( x - k ) ^ 2, where (h,k) is the vertex.

the vertex of the quadratic function is (2,5)

Plug the numbers into the equation which gives you y - 5 = a( x-2)^2

Bring over the five and you have y = a(x-2)^2 +5

That narrows down your options to two answers. The graph opens upward, so the value of a is positive. That leaves one option y = 2(x-2)^2+5.