Cost of admission to a town fair was $8 for adults and $5 for children. If 206 people attended the fair, and ticket sales totaled $1408, how many adult tickets were sold?

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Step-by-step explanation:

Step one:

let the number of adults be x

and the number of children be y

cost of tickets $8 for adults and $5 for children

total tickets is 206

total money made=$1408

Step two:

The system of equation is

x+y=2061

8x+5y=14082

from 1 x=206-y

put x=206-y in equation 2 we have

8(206-y)+5y=1408

1648-8y+5y=1408

-3y=1408-1648

-3y=-240

divide both sides by -3

y=80 children tickets

put y=80 in x+y=2061

x+80=206

x=206-80

x=126 adult tickest

126 adult tickest

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

step-by-step explanation:

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