Find an equation for a line that passes through points -4,3 and 6,5

First you would want to find the slope. The equation for slope is y2-y1/x2-x1.

So the slope would be 5-3/ 6-(-4). Two negatives make a positive so it would be 5-3/6+4 or 2/10 which can be simplified to 1/2.

Next you used the point slope form equation. y-y1 =m(x-x1)

m is the slope we just found: 1/2
the equation would be = y-3=1/2(x-(-4))

two negatives make a positive so the equation would now be y-3=1/2(x+4)

You then distribute the x to what is in the parenthesis

y-3=1/2x+2
then add the 3 to both sides

you’re equation should be y=1/2+5