Giovanna owns a farm. she is going to randomly select one animal to present at the state fair. she has 666 pigs, 777 chickens, and 101010 cows. what is \text{p(chicken})p(chicken)p, left parenthesis, c, h, i, c, k, e, n, right parenthesis? if necessary, round your answer to 222 decimal places.

Giovanna owns a farm. She is going to randomly select one animal to present at the state fair. She has 6 pigs, 7 chickens, and 10 cows.  What is the probability she will select a chicken?

There are 23 animals in all. (6+7+10 = 23)

Probability of choosing a chicken : 7/23

Probability of choosing a pig: 6/23

Probability of choosing a cow: 10/23

Step-by-step explanation:

Given: The number of pigs in Giovanna's farm = 6

The number of chickens = 7

The number of cows = 10

Therefore, the total number of animals in the farm =

Now, the probability of drawing a chicken from all the animals in the farm is given by :-

Hence,

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2