A quadratic function has its vertex at the point (- 3, 8) . The function passes through the point (0, 0) . When written in vertex form, the function is f(x) = a * (x - h) ^ 2 + k where: a =

h =

k =

f(x) = -8/3(x+3)+8

a = -8/3

b = technically equals -3 but when we plug it in it gets turned into 3 *double negative

k = 8

Step-by-step explanation:

Vertex: (h,k)

Use the points (0,0) and (-3,8) to find the slope

y2-y1/x2- x1

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step-by-step explanation:

because i said it is