Suppose that a dimension x and the area A of a shape are differentiable functions of t. Write an equation that relates to .

Complete question is;

Suppose that a dimension x and the area A = 2x² of a shape are differentiable functions of t. Write an equation that relates dA/dt to dx/dt.

Step-by-step explanation:

Since A = 2x²

Let's differentiate both sides with respect to x.

dA/dx = 4x

Now, we want to find the relationship between dA/dt and dx/dt

dA/dt can be expressed as;

(dA/dt) = (dA/dx) × (dx/dt)

Thus;

dA/dt = 4x(dx/dt)

Thus, the equation that relates dA/dt to dx/dt is;

dA/dt = 4x(dx/dt)

or

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh