Two water tanks are being filled. The water in Tank A is 3 inches deep, and the depth of the water increases 4 inches every hour. The water in Tank B is 10 inches deep, and the depth is increasing by 2 inches every hour.
Write an inequality to determine when the water in Tank A will be deeper than the water in Tank B.

Define the variable:

Write the inequality:

variable: number of hours

inequality (unsimplified): 4x+3 > 2x+10

inequality (simplified): x > 3.5

at least 4 hours

Step-by-step explanation:

we can use mx+b to solve this. m will be the rate at which the water level rises and b will be your stating point. x defines the hour; this is your varible as it can change

Tank A: 4x+3

Tank B: 2x+10

since we want to find when tank a will have be deeper than tank b, we set the inequality to solve for greater than tank a: 4x+3 > 2x+10

subtract 3 to both sides: 4x > 2x + 7

subtract 2x to both sides: 2x > 7

divide both sides by 2: x > 3.5

in 4 days he will run   12/14

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: