How many solutions does 9x^2+ 6x + 1 = 0 have? (a) one real and one nonreal complex solution
(b) two distinct real solutions
(c) one real solution with multiplicity 2
(d) two nonreal complex solutions
(e) one nonreal complex solution with multiplicity 2

(c). one real solution

Step-by-step explanation:

9x² + 6x + 1 = 0

D = 6² - 4(9)(1) = 0 ⇒ one real solution with multiplicity 2

i dont know it

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b