Asha makes a conjecture that the perimeter of a square whose sides are an odd integer is always even. Which choice is the best proof of her conjecture?

Bottom left corner

Let n be an odd number. Because 4n is a multiple of 2, it is an even number.

Explanation:

The square has a side length of n, so its perimeter is 4n since n+n+n+n = 4n.

We can rewrite 4n as 2*2n = 2m where m = 2n is an integer. Any number in the form 2*(some integer) is always even. Even numbers always have 2 as a factor.

So whenever it comes to proving something is even, the ultimate goal is to get it into the form 2*(some integer). If we can do this, then the number is even. If not, then the number is odd.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation: