PLZ HELP Use your knowledge of solving equations with variables on both sides of the equal sign to solve the following problem.
A square and a rectangle have the same perimeter. The square has a side length of 6x units. The rectangle has a length of (2x + 4) units and a width of 16 units. What will be the perimeter of both the rectangle and the square? and don't just give me an answer, I need to understand this.
Answer choices:
26
56
48
2

a

Step-by-step explanation:

48

Step-by-step explanation:

Perimeter of square = 4 x 6x

Perimeter = 24x

P = 2l + 2w

P = 2(2x + 4) + 2(16)

P = 4x + 8 + 32

P = 4x + 40

Perimeter of square = perimeter of rectangle

24x = 4x + 40

-4x      -4x

20x = 40

20      20

x = 2

Perimeter of square = 24x

Perimeter of square = 24(2)

Perimeter of square = 48

Perimeter of rectangle = 4x + 40

Perimeter of rectangle = 4(2) + 40

Perimeter of rectangle = 8 + 40

Perimeter of rectangle = 48

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)