A square and a rectangle have the same perimeter. The square has a side length of 6x units. The rectangle has a length of (2x + 4) units and a width of 16 units. What will be the perimeter of both the rectangle and the square?

48

Step-by-step explanation:

Perimeter of square = 4 x 6x

Perimeter of square = 24x

Perimeter of rectangle = 2l + 2w

Perimeter of rectangle = 2(2x+4) + 2(16)

Perimeter of rectangle = 4x + 8 + 32

Perimeter of rectangle = 4x + 40

Perimeter of rectangle = Perimeter of square

4x + 40 = 24x

-4x             -4x

40 = 20x

20     20

x = 2

Perimeter of square = 24x

Perimeter of square = 24(2)

Perimeter of square = 48

Perimeter of rectangle = 4x + 40

Perimeter of rectangle = 4(2) + 40

Perimeter of rectangle = 8 + 40

Perimeter of rectangle =48

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a