In the rope climb, a 75 kg athlete climbs a vertical distance of 5.0 m in 9.0 s. What minimum power output was used to accomplish this feat? ___ W

The minimum power output used to accomplish this feat is 408.625 watts.

Step-by-step explanation:

The minimum power is that needed to overcome potential gravitational energy at constant velocity. From Principle of Energy Conservation, Work-Energy Theorem and definition of power we obtain the following relationship:

(Eq. 1)

Where:

- Mass of the athlete, measured in kilograms.

- Gravitational constant, measured in meters per square second.

- Climbing rate, measured in meters per second.

- Power, measured in watts.

By the consideration of constant velocity, we get that the climbing rate is represented by:

(Eq. 2)

Where:

- Travelled distance, measured in meters.

- Time, measured in seconds.

And by substituting on (Eq. 1), the following expression is found:

If we know that , , and , then the minimum power output is:

The minimum power output used to accomplish this feat is 408.625 watts.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

sure i'm up for it

step-by-step explanation: