Mathematics, 09.11.2020 16:20 vane1648
EXAMPLE 5 Suppose that f(0) = β4 and f '(x) β€ 5 for all values of x. How large can f(2) possibly be? SOLUTION We are given that f is differentiable (and therefore continuous) everywhere. In particular, we can apply the Mean Value Theorem on the interval [0, 2] . There exists a number c such that f(2) β f(0) = f '(c) β 0 so f(2) = f(0) + f '(c) = β4 + f '(c). We are given that f '(x) β€ 5 for all x, so in particular we know that f '(c) β€ . Multiplying both sides of this inequality by 2, we have 2f '(c) β€ , so f(2) = β4 + f '(c) β€ β4 + = . The largest possible value for f(2) is .
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Which statements regarding efg are true? check all that apply.
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6x + 3y = -6 2x + y = -2 a. x = 0, y = -2 b. infinite solutions c. x = -1, y = 0 d. no solution
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EXAMPLE 5 Suppose that f(0) = β4 and f '(x) β€ 5 for all values of x. How large can f(2) possibly be?...
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