examine the spinner at right. If the central angle of region A is 7 calculate the expected value of one spin. Round to the nearest hundredth..pls hurry

The whole angle on a circle is equal to 360°.

This means that:

∠A + ∠B = 360°.

Here we know that ∠A = 7°

Then ∠B = 360° - 7° = 353°

Now, if the probability is evenly distributed for all the angles, then the probability that the spinner lands in A is equal to the quotient between the measure of the angle A, and the measure of the total circumference, this will be:

Pa = 7°/360° = 0.019

And the same for B:

Pb = 353°/360° = 0.981

Now, the expected value can be calculated as:

Ev = ∑xₙ*pₙ

Where xₙ is the event n, and pₙ is its probability.

Then:

x₁ = A = 100

p₁ = Pa = 0.019

x₂ = B = 2

p₂ = Pb = 0.981

The expected vale will be:

Ev = 100*0.019 + 2*0.981 = 3.862

Rounding to the nearest hundredth, the second digit after the decimal point, we have:

Ev = 3.86

i'm sorry i don't know

step-by-step explanation: