On interval 0 ≤ x < 2π, where are the x-intercepts of y = cos(2x)?

The answer is choice D because we plug in something like x = pi/4 and it leads to

y = cos(2x)

y = cos(2*pi/4)

y = cos(pi/2)

y = 0

Use the unit circle to see why cos(pi/2) = 0.

Since we get y = 0 as a result, this shows x = pi/4 is one of the x intercepts.

You'll also get y = 0 if you plug in x = 3pi/4, x = 5pi/4, and x = 7pi/4. All of these values are on the interval

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

do you have an easier question cause this shh is hard like theheck

step-by-step explanation: