A consumer group is investigating the number of flights at a certain airline that are overbooked. They conducted a simulation to estimate the probability of overbooked flights in the next 5 flights. The results of 1,000 trials are shown in the following histogram.

The probability that atleast four of the next five flights will be overbooked is the sum of the probabilities of having 4 or 5 flights overbooked which is 0.446

The probability of having atleast 4 flights overbooked can be defined as :

P(X ≥ 5) = P(X = 4) + P(X = 5)

From the probability distribution displayed on the histogram :

P(X ≥ 5) = 0.332 + 0.114 = 0.446

Therefore, the probability of having atleast 4 flights overbooked ls 0.446

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answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6