Find the distance between the two points G(-1,-5) and H(3,-8)

5.099

Step by step explanations:

Input Data :

Point 1(xA,yA)(xA,yA) = (4, 3)

Point 2(xB,yB)(xB,yB) = (3, -2)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2

= √(−1)2+(−5)2(-1)2+(-5)2

= √1+251+25

= √2626 = 5.099

Distance between points (4, 3) and (3, -2) is 5.099

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|