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Mathematics, 06.11.2020 23:50 tiwaribianca475
What is the solution to the equation 23(yβ6)=β(y+2)+1 2 3 ( y - 6 ) = - ( y + 2 ) + 1 ?
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What is the solution to the equation 23(yβ6)=β(y+2)+1 2 3 ( y - 6 ) = - ( y + 2 ) + 1 ?...
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