When designing a study to determine this population proportion, what is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.04

601

Step-by-step explanation:

The formula to find the minimum sample size(n) , if the prior population proportion is unknown:

, where E = margin of error , = critical z-value for confidence level c.

Given : E  = 0.04

Z-value for 95% confidence = 1.96

So, the minimum sample size required =

Hence, the minimum sample size required = 601

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363